10x^2=-530x

Solution for 10x^2=-530x equation:

10x^2=-530x

We move all terms to the left:

10x^2-(-530x)=0

We get rid of parentheses

10x^2+530x=0

a = 10; b = 530; c = 0;
Δ = b2-4ac
Δ = 5302-4·10·0
Δ = 280900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{280900}=530$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(530)-530}{2*10}=\frac{-1060}{20}
=-53
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(530)+530}{2*10}=\frac{0}{20}
=0
$